y^2-y-12/4-y

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Solution for y^2-y-12/4-y equation: 


y in (-oo:+oo)

y^2-y-y-(12/4) = 0

y^2-y-y-3 = 0

y^2-2*y-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

y = (16^(1/2)+2)/(1*2) or y = (2-16^(1/2))/(1*2)

y = 3 or y = -1

y in { -1, 3 }

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